Optimal. Leaf size=528 \[ \frac {\sqrt {b} \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (8 d^2 (A-C)-12 B c d+15 c^2 C\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{4 d^{7/2} f}+\frac {b \left (d^2 (4 A+C)-4 B c d+5 c^2 C\right ) (a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)}}{2 d^2 f \left (c^2+d^2\right )}-\frac {2 \left (A d^2-B c d+c^2 C\right ) (a+b \tan (e+f x))^{5/2}}{d f \left (c^2+d^2\right ) \sqrt {c+d \tan (e+f x)}}-\frac {b \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)} \left (3 (b c-a d) \left (d^2 (4 A+C)-4 B c d+5 c^2 C\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right )}{4 d^3 f \left (c^2+d^2\right )}-\frac {(a-i b)^{5/2} (i A+B-i C) \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{f (c-i d)^{3/2}}-\frac {(a+i b)^{5/2} (B-i (A-C)) \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{f (c+i d)^{3/2}} \]
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Rubi [A] time = 8.19, antiderivative size = 528, normalized size of antiderivative = 1.00, number of steps used = 15, number of rules used = 9, integrand size = 49, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.184, Rules used = {3645, 3647, 3655, 6725, 63, 217, 206, 93, 208} \[ \frac {\sqrt {b} \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (8 d^2 (A-C)-12 B c d+15 c^2 C\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{4 d^{7/2} f}+\frac {b \left (d^2 (4 A+C)-4 B c d+5 c^2 C\right ) (a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)}}{2 d^2 f \left (c^2+d^2\right )}-\frac {b \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)} \left (3 (b c-a d) \left (d^2 (4 A+C)-4 B c d+5 c^2 C\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right )}{4 d^3 f \left (c^2+d^2\right )}-\frac {2 \left (A d^2-B c d+c^2 C\right ) (a+b \tan (e+f x))^{5/2}}{d f \left (c^2+d^2\right ) \sqrt {c+d \tan (e+f x)}}-\frac {(a-i b)^{5/2} (i A+B-i C) \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{f (c-i d)^{3/2}}-\frac {(a+i b)^{5/2} (B-i (A-C)) \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{f (c+i d)^{3/2}} \]
Antiderivative was successfully verified.
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Rule 63
Rule 93
Rule 206
Rule 208
Rule 217
Rule 3645
Rule 3647
Rule 3655
Rule 6725
Rubi steps
\begin {align*} \int \frac {(a+b \tan (e+f x))^{5/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{(c+d \tan (e+f x))^{3/2}} \, dx &=-\frac {2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt {c+d \tan (e+f x)}}+\frac {2 \int \frac {(a+b \tan (e+f x))^{3/2} \left (\frac {1}{2} (A d (a c+5 b d)+(5 b c-a d) (c C-B d))+\frac {1}{2} d ((A-C) (b c-a d)+B (a c+b d)) \tan (e+f x)+\frac {1}{2} b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) \tan ^2(e+f x)\right )}{\sqrt {c+d \tan (e+f x)}} \, dx}{d \left (c^2+d^2\right )}\\ &=-\frac {2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt {c+d \tan (e+f x)}}+\frac {b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac {\int \frac {\sqrt {a+b \tan (e+f x)} \left (\frac {1}{4} \left (-b (3 b c+a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )+4 a d (A d (a c+5 b d)+(5 b c-a d) (c C-B d))\right )+d^2 \left (2 a b (A c-c C+B d)+a^2 (B c-(A-C) d)-b^2 (B c-(A-C) d)\right ) \tan (e+f x)-\frac {1}{4} b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \tan ^2(e+f x)\right )}{\sqrt {c+d \tan (e+f x)}} \, dx}{d^2 \left (c^2+d^2\right )}\\ &=-\frac {2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt {c+d \tan (e+f x)}}-\frac {b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac {b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac {\int \frac {\frac {1}{8} \left (8 a^3 d^3 (A c-c C+B d)+3 a^2 b d^2 \left (5 c^2 C-8 B c d+(8 A-3 C) d^2\right )+b^3 c \left (15 c^3 C-12 B c^2 d+c (8 A+7 C) d^2-4 B d^3\right )-2 a b^2 d \left (15 c^3 C-10 B c^2 d+3 c (4 A+C) d^2+2 B d^3\right )\right )+d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right ) \tan (e+f x)+\frac {1}{8} b \left (c^2+d^2\right ) \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right ) \tan ^2(e+f x)}{\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}} \, dx}{d^3 \left (c^2+d^2\right )}\\ &=-\frac {2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt {c+d \tan (e+f x)}}-\frac {b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac {b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac {\operatorname {Subst}\left (\int \frac {\frac {1}{8} \left (8 a^3 d^3 (A c-c C+B d)+3 a^2 b d^2 \left (5 c^2 C-8 B c d+(8 A-3 C) d^2\right )+b^3 c \left (15 c^3 C-12 B c^2 d+c (8 A+7 C) d^2-4 B d^3\right )-2 a b^2 d \left (15 c^3 C-10 B c^2 d+3 c (4 A+C) d^2+2 B d^3\right )\right )+d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right ) x+\frac {1}{8} b \left (c^2+d^2\right ) \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right ) x^2}{\sqrt {a+b x} \sqrt {c+d x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{d^3 \left (c^2+d^2\right ) f}\\ &=-\frac {2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt {c+d \tan (e+f x)}}-\frac {b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac {b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac {\operatorname {Subst}\left (\int \left (\frac {b \left (c^2+d^2\right ) \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right )}{8 \sqrt {a+b x} \sqrt {c+d x}}+\frac {d^3 \left (a^3 (A c-c C+B d)-3 a b^2 (A c-c C+B d)-3 a^2 b (B c-(A-C) d)+b^3 (B c-(A-C) d)\right )+d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right ) x}{\sqrt {a+b x} \sqrt {c+d x} \left (1+x^2\right )}\right ) \, dx,x,\tan (e+f x)\right )}{d^3 \left (c^2+d^2\right ) f}\\ &=-\frac {2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt {c+d \tan (e+f x)}}-\frac {b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac {b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac {\operatorname {Subst}\left (\int \frac {d^3 \left (a^3 (A c-c C+B d)-3 a b^2 (A c-c C+B d)-3 a^2 b (B c-(A-C) d)+b^3 (B c-(A-C) d)\right )+d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right ) x}{\sqrt {a+b x} \sqrt {c+d x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{d^3 \left (c^2+d^2\right ) f}+\frac {\left (b \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right )\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{8 d^3 f}\\ &=-\frac {2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt {c+d \tan (e+f x)}}-\frac {b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac {b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac {\operatorname {Subst}\left (\int \left (\frac {-d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right )+i d^3 \left (a^3 (A c-c C+B d)-3 a b^2 (A c-c C+B d)-3 a^2 b (B c-(A-C) d)+b^3 (B c-(A-C) d)\right )}{2 (i-x) \sqrt {a+b x} \sqrt {c+d x}}+\frac {d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right )+i d^3 \left (a^3 (A c-c C+B d)-3 a b^2 (A c-c C+B d)-3 a^2 b (B c-(A-C) d)+b^3 (B c-(A-C) d)\right )}{2 (i+x) \sqrt {a+b x} \sqrt {c+d x}}\right ) \, dx,x,\tan (e+f x)\right )}{d^3 \left (c^2+d^2\right ) f}+\frac {\left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {c-\frac {a d}{b}+\frac {d x^2}{b}}} \, dx,x,\sqrt {a+b \tan (e+f x)}\right )}{4 d^3 f}\\ &=-\frac {2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt {c+d \tan (e+f x)}}-\frac {b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac {b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac {\left ((a+i b)^3 (A+i B-C) (i c+d)\right ) \operatorname {Subst}\left (\int \frac {1}{(i-x) \sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{2 \left (c^2+d^2\right ) f}+\frac {\left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right ) \operatorname {Subst}\left (\int \frac {1}{1-\frac {d x^2}{b}} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{4 d^3 f}+\frac {\left (d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right )+i d^3 \left (a^3 (A c-c C+B d)-3 a b^2 (A c-c C+B d)-3 a^2 b (B c-(A-C) d)+b^3 (B c-(A-C) d)\right )\right ) \operatorname {Subst}\left (\int \frac {1}{(i+x) \sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{2 d^3 \left (c^2+d^2\right ) f}\\ &=\frac {\sqrt {b} \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{4 d^{7/2} f}-\frac {2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt {c+d \tan (e+f x)}}-\frac {b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac {b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac {\left ((a-i b)^3 (i A+B-i C)\right ) \operatorname {Subst}\left (\int \frac {1}{-a+i b-(-c+i d) x^2} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{(c-i d) f}+\frac {\left ((a+i b)^3 (A+i B-C) (i c+d)\right ) \operatorname {Subst}\left (\int \frac {1}{a+i b-(c+i d) x^2} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{\left (c^2+d^2\right ) f}\\ &=-\frac {(a-i b)^{5/2} (i A+B-i C) \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{(c-i d)^{3/2} f}-\frac {(a+i b)^{5/2} (B-i (A-C)) \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{(c+i d)^{3/2} f}+\frac {\sqrt {b} \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{4 d^{7/2} f}-\frac {2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt {c+d \tan (e+f x)}}-\frac {b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac {b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}\\ \end {align*}
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Mathematica [C] time = 44.53, size = 1653959, normalized size = 3132.50 \[ \text {Result too large to show} \]
Warning: Unable to verify antiderivative.
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fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F(-1)] time = 180.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a +b \tan \left (f x +e \right )\right )^{\frac {5}{2}} \left (A +B \tan \left (f x +e \right )+C \left (\tan ^{2}\left (f x +e \right )\right )\right )}{\left (c +d \tan \left (f x +e \right )\right )^{\frac {3}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (a+b\,\mathrm {tan}\left (e+f\,x\right )\right )}^{5/2}\,\left (C\,{\mathrm {tan}\left (e+f\,x\right )}^2+B\,\mathrm {tan}\left (e+f\,x\right )+A\right )}{{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{3/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \tan {\left (e + f x \right )}\right )^{\frac {5}{2}} \left (A + B \tan {\left (e + f x \right )} + C \tan ^{2}{\left (e + f x \right )}\right )}{\left (c + d \tan {\left (e + f x \right )}\right )^{\frac {3}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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